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find the rate of change of depth of water when water is 8 ft deep?
a conical tank with height is decline is shown in the top 10 ft and 12 ft deep. water is flowing in the tank at a rate of about 10 ft Cubed minute. found the rate of change of depth of water when water is 8 ft deep.
Radius at the top of tank is 10 / 2 = 5ft. 8ft beam. So the end is 8 * 5 / 12 = 10 / 3 ft tank cross-sectional area in this depth is: pi (10 / 3) ^ 2 ^ 2 ft.. Rate The increase in water depth is therefore 10 / [pi (10 / 3) ^ 2] = 9 / drinks 10 = 0.286 ft / sec.
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